What is the general solution for (1+tan(x))/(sin(x))=0 ?

The general solution for (1+tan(x))/(sin(x))=0 is x=(3pi)/4+pin

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(1+tan(x))/(sin(x))=0

\frac{1 + tan ( x )}{sin ( x )} = 0

x = \frac{3 π}{4} + πn

Solution steps

\frac{1 + tan ( x )}{sin ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

1 + tan (x) = 0

Move

1

to the right side

tan (x) = - 1

General solutions for

tan (x) = - 1

x = \frac{3 π}{4} + πn

4 sin^{2} (x) + 2 sin (x) - 2 = 0

x, cos (x y) = 0

- 6 cos (x) sin (x) = 0

tan (2 x - \frac{π}{6}) = 3

sin^{2} (x) + 6 sin (x) = 2 sin (x) - 3

What is the general solution for (1+tan(x))/(sin(x))=0 ?
The general solution for (1+tan(x))/(sin(x))=0 is x=(3pi)/4+pin