What is the general solution for 2+sec(x)=0 ?

The general solution for 2+sec(x)=0 is x=(2pi)/3+2pin,x=(4pi)/3+2pin

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2+sec(x)=0

2 + sec (x) = 0

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

Solution steps

2 + sec (x) = 0

Move

2

to the right side

sec (x) = - 2

General solutions for

sec (x) = - 2

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

cos (x) = \frac{3}{2}, sin (x), \frac{3 π}{2} \leq x \leq 2 π

sec (x) = 9

cot (x + 1) = 0

cot^{2} (x) = \frac{1 + sin ( x )}{1 + cos ( x )}

0.7 sin (3 π t) - 3 π cos (3 π t) = 0

What is the general solution for 2+sec(x)=0 ?
The general solution for 2+sec(x)=0 is x=(2pi)/3+2pin,x=(4pi)/3+2pin