What is the general solution for 3cos(θ)=-3sin(-θ) ?

The general solution for 3cos(θ)=-3sin(-θ) is θ= pi/4+pin

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3cos(θ)=-3sin(-θ)

3 cos (θ) = - 3 sin (- θ)

θ = \frac{π}{4} + πn

Solution steps

3 cos (θ) = - 3 sin (- θ)

Rewrite using trig identities

3 cos (θ) = 3 sin (θ)

Subtract

3 sin (θ)

from both sides

3 cos (θ) - 3 sin (θ) = 0

Rewrite using trig identities

3 - 3 tan (θ) = 0

Move

3

to the right side

- 3 tan (θ) = - 3

Divide both sides by

- 3

tan (θ) = 1

General solutions for

tan (θ) = 1

θ = \frac{π}{4} + πn

3 sec (x) - 6 = 0

sin (2 x) = \frac{1}{3}

4 sin (θ) - 3 = 2 sin (θ)

cos (2 x) = - 0.5

5 cos (x) - 5 sin (x) = 0

What is the general solution for 3cos(θ)=-3sin(-θ) ?
The general solution for 3cos(θ)=-3sin(-θ) is θ= pi/4+pin