What is the general solution for 6arccos(2x)=5pi ?

The general solution for 6arccos(2x)=5pi is x=-(sqrt(3))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6arccos(2x)=5pi

6 arccos (2 x) = 5 π

x = - \frac{3}{4}

Solution steps

6 arccos (2 x) = 5 π

Divide both sides by

6

arccos (2 x) = \frac{5 π}{6}

Apply trig inverse properties

2 x = - \frac{3}{2}

Solve

2 x = - \frac{3}{2} : x = - \frac{3}{4}

x = - \frac{3}{4}

2 sin (x) + cot (x) - csc (x) = 0

cosh (x) = \frac{5}{3}

2 cos^{2} (x) - 3 sin (x) + 2 = 0

sin (θ) = 0.75

x, sin (x) + cos (x) = 1

What is the general solution for 6arccos(2x)=5pi ?
The general solution for 6arccos(2x)=5pi is x=-(sqrt(3))/4