What is the general solution for cos(5x)=1,0<= x<= pi/2 ?

The general solution for cos(5x)=1,0<= x<= pi/2 is x=0,x=(2pi)/5

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cos(5x)=1,0<= x<= pi/2

cos (5 x) = 1, 0 \leq x \leq \frac{π}{2}

x = 0, x = \frac{2 π}{5}

Solution steps

cos (5 x) = 1, 0 \leq x \leq \frac{π}{2}

General solutions for

cos (5 x) = 1

5 x = 0 + 2 πn

Solve

5 x = 0 + 2 πn : x = \frac{2 πn}{5}

x = \frac{2 πn}{5}

Solutions for the range

0 \leq x \leq \frac{π}{2}

x = 0, x = \frac{2 π}{5}

sec (x) = - 1 + tan (x)

cos (2 x) + 2 cos^{2} (x) = 0

x, csc (x) + cot (x) = 1

sin (θ) = - 5

sin (x) - 1 = cos (x) - 1

What is the general solution for cos(5x)=1,0<= x<= pi/2 ?
The general solution for cos(5x)=1,0<= x<= pi/2 is x=0,x=(2pi)/5