What is the general solution for 2sin(4x)=0 ?

The general solution for 2sin(4x)=0 is x=(pin)/2 ,x= pi/4+(pin)/2

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2sin(4x)=0

2 sin (4 x) = 0

x = \frac{πn}{2}, x = \frac{π}{4} + \frac{πn}{2}

Solution steps

2 sin (4 x) = 0

Divide both sides by

2

sin (4 x) = 0

General solutions for

sin (4 x) = 0

4 x = 0 + 2 πn, 4 x = π + 2 πn

Solve

4 x = 0 + 2 πn : x = \frac{πn}{2}

Solve

4 x = π + 2 πn : x = \frac{π}{4} + \frac{πn}{2}

x = \frac{πn}{2}, x = \frac{π}{4} + \frac{πn}{2}

9 \cdot csc (x) = 63, (- \infty, \infty)

cos (2 x - \frac{π}{2}) = 1

tan (x) = - 2

sin (θ) = \frac{1}{8}

5 sin (θ) + 1 = 0

What is the general solution for 2sin(4x)=0 ?
The general solution for 2sin(4x)=0 is x=(pin)/2 ,x= pi/4+(pin)/2