What is the general solution for sin(1/2 x)-1=0 ?

The general solution for sin(1/2 x)-1=0 is x=pi+4pin

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sin(1/2 x)-1=0

sin (\frac{1}{2} x) - 1 = 0

x = π + 4 πn

Solution steps

sin (\frac{1}{2} x) - 1 = 0

Move

1

to the right side

sin (\frac{1}{2} x) = 1

General solutions for

sin (\frac{1}{2} x) = 1

\frac{1}{2} x = \frac{π}{2} + 2 πn

Solve

\frac{1}{2} x = \frac{π}{2} + 2 πn : x = π + 4 πn

x = π + 4 πn

- \frac{1}{16} sin (\frac{x}{4}) = 0

sec (x) = - 2, π < x < \frac{3 π}{2}

sin (x) cos (x) = cos^{2} (x)

x, sin (x - y) = 0

cos (2 θ) = 0.4

What is the general solution for sin(1/2 x)-1=0 ?
The general solution for sin(1/2 x)-1=0 is x=pi+4pin