What is the general solution for 3sqrt(2)cos(θ)+1=-2,0<= θ<2pi ?

The general solution for 3sqrt(2)cos(θ)+1=-2,0<= θ<2pi is θ=(3pi)/4 ,θ=(5pi)/4

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3sqrt(2)cos(θ)+1=-2,0<= θ<2pi

32 cos (θ) + 1 = - 2, 0 \leq θ < 2 π

θ = \frac{3 π}{4}, θ = \frac{5 π}{4}

Solution steps

32 cos (θ) + 1 = - 2, 0 \leq θ < 2 π

Move

1

to the right side

32 cos (θ) = - 3

Divide both sides by

32

cos (θ) = - \frac{2}{2}

General solutions for

cos (θ) = - \frac{2}{2}

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

Solutions for the range

0 \leq θ < 2 π

θ = \frac{3 π}{4}, θ = \frac{5 π}{4}

cos (u) = - \frac{15}{17}

2 cos (\frac{x}{3}) = 1

0 = 3 tan (x)

sin (b) = \frac{4}{5}

14 (1 - cos (θ)) = sin^{2} (θ)

What is the general solution for 3sqrt(2)cos(θ)+1=-2,0<= θ<2pi ?
The general solution for 3sqrt(2)cos(θ)+1=-2,0<= θ<2pi is θ=(3pi)/4 ,θ=(5pi)/4