What is the general solution for 14(1-cos(θ))=sin^2(θ) ?

The general solution for 14(1-cos(θ))=sin^2(θ) is θ=2pin

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14(1-cos(θ))=sin^2(θ)

14 (1 - cos (θ)) = sin^{2} (θ)

θ = 2 πn

Solution steps

14 (1 - cos (θ)) = sin^{2} (θ)

Subtract

sin^{2} (θ)

from both sides

14 (1 - cos (θ)) - sin^{2} (θ) = 0

Rewrite using trig identities

13 + cos^{2} (θ) - 14 cos (θ) = 0

Solve by substitution

cos (θ) = 13, cos (θ) = 1

cos (θ) = 13 :

No Solution

cos (θ) = 1 : θ = 2 πn

Combine all the solutions

θ = 2 πn

3 tan (x) sin (x) - 3 tan (x) = 0

4 cos^{2} (x) + 43 cos (x) + 3 = 0

4 cos^{2} (β) - 4 cos (β) = 3

x, cot (x) = 1

sin^{4} (x) + cos^{4} (x) = \frac{5}{8}

What is the general solution for 14(1-cos(θ))=sin^2(θ) ?
The general solution for 14(1-cos(θ))=sin^2(θ) is θ=2pin