What is the general solution for tan(θ)=19,0<= θ<2pi ?

The general solution for tan(θ)=19,0<= θ<2pi is θ=1.51821…,θ=1.51821…+pi

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tan(θ)=19,0<= θ<2pi

tan (θ) = 19, 0 \leq θ < 2 π

θ = 1.51821 \dots, θ = 1.51821 \dots + π

Solution steps

tan (θ) = 19, 0 \leq θ < 2 π

Apply trig inverse properties

θ = arctan (19) + πn

Solutions for the range

0 \leq θ < 2 π

θ = arctan (19), θ = arctan (19) + π

Show solutions in decimal form

θ = 1.51821 \dots, θ = 1.51821 \dots + π

cos (2 θ) - 2 cos (θ) = - 1

(sec (x) - 2) (3 sec (x) + 2) = 0

csc (x) cot (x) = 2

2 sin^{2} (x) = 2 + cos (2 x)

2 tan^{2} (x) - sec (x) = 1

What is the general solution for tan(θ)=19,0<= θ<2pi ?
The general solution for tan(θ)=19,0<= θ<2pi is θ=1.51821…,θ=1.51821…+pi