What is the general solution for 2cos^2(x)+3cos(x)=2,0<= x<= 2pi ?

The general solution for 2cos^2(x)+3cos(x)=2,0<= x<= 2pi is x= pi/3 ,x=(5pi)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2cos^2(x)+3cos(x)=2,0<= x<= 2pi

2 cos^{2} (x) + 3 cos (x) = 2, 0 \leq x \leq 2 π

x = \frac{π}{3}, x = \frac{5 π}{3}

Solution steps

2 cos^{2} (x) + 3 cos (x) = 2, 0 \leq x \leq 2 π

Solve by substitution

cos (x) = \frac{1}{2}, cos (x) = - 2

cos (x) = \frac{1}{2}, 0 \leq x \leq 2 π : x = \frac{π}{3}, x = \frac{5 π}{3}

cos (x) = - 2, 0 \leq x \leq 2 π :

No Solution

Combine all the solutions

x = \frac{π}{3}, x = \frac{5 π}{3}

cos (θ) = \frac{7}{11}

(1 - sin^{2} (x)) \cdot 2 - 3 sin (x) = 0

sin (\frac{θ}{2}) = sin (θ)

2 tan (x) = 1

2 tan (x) = 3

What is the general solution for 2cos^2(x)+3cos(x)=2,0<= x<= 2pi ?
The general solution for 2cos^2(x)+3cos(x)=2,0<= x<= 2pi is x= pi/3 ,x=(5pi)/3