What is the general solution for (tan(x)-1)/(1+tan(x))=0 ?

The general solution for (tan(x)-1)/(1+tan(x))=0 is x= pi/4+pin

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(tan(x)-1)/(1+tan(x))=0

\frac{tan ( x ) - 1}{1 + tan ( x )} = 0

x = \frac{π}{4} + πn

Solution steps

\frac{tan ( x ) - 1}{1 + tan ( x )} = 0

Solve by substitution

tan (x) = 1

tan (x) = 1 : x = \frac{π}{4} + πn

Combine all the solutions

x = \frac{π}{4} + πn

arccos (x) + arccos (2 x) = \frac{π}{2}

sin^{2} (x) + sin (x) = cos^{2} (x)

- 2 - 3 sin (x) = 1 - 6 sin (x)

x, 4 cos (x) sin (y) = 1

- 2 csc^{2} (x) = 0

What is the general solution for (tan(x)-1)/(1+tan(x))=0 ?
The general solution for (tan(x)-1)/(1+tan(x))=0 is x= pi/4+pin