What is the general solution for sec(θ+20)=sqrt(3) ?

The general solution for sec(θ+20)=sqrt(3) is θ=0.95531…+360n-20,θ=360-0.95531…+360n-20

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sec(θ+20)=sqrt(3)

sec (θ + 2 0^{\circ}) = 3

θ = 0.95531 \dots + 36 0^{\circ} n - 2 0^{\circ}, θ = 36 0^{\circ} - 0.95531 \dots + 36 0^{\circ} n - 2 0^{\circ}

Solution steps

sec (θ + 2 0^{\circ}) = 3

Apply trig inverse properties

θ + 2 0^{\circ} = arcsec (3) + 36 0^{\circ} n, θ + 2 0^{\circ} = 36 0^{\circ} - arcsec (3) + 36 0^{\circ} n

Solve

θ + 2 0^{\circ} = arcsec (3) + 36 0^{\circ} n : θ = arcsec (3) + 36 0^{\circ} n - 2 0^{\circ}

Solve

θ + 2 0^{\circ} = 36 0^{\circ} - arcsec (3) + 36 0^{\circ} n : θ = 36 0^{\circ} - arcsec (3) + 36 0^{\circ} n - 2 0^{\circ}

θ = arcsec (3) + 36 0^{\circ} n - 2 0^{\circ}, θ = 36 0^{\circ} - arcsec (3) + 36 0^{\circ} n - 2 0^{\circ}

Show solutions in decimal form

θ = 0.95531 \dots + 36 0^{\circ} n - 2 0^{\circ}, θ = 36 0^{\circ} - 0.95531 \dots + 36 0^{\circ} n - 2 0^{\circ}

tan (θ) = \frac{7.7}{14}

cos (x) = \frac{3}{3}

3 + 4 cos (θ) = - 1

cot (x) tan (x) = sec (x) csc (x)

sin (x + \frac{π}{2}) - sin (x - \frac{π}{2}) = 2

What is the general solution for sec(θ+20)=sqrt(3) ?
The general solution for sec(θ+20)=sqrt(3) is θ=0.95531…+360n-20,θ=360-0.95531…+360n-20