What is the general solution for solvefor x,tan(x)csc(x)= 1/f ?

The general solution for solvefor x,tan(x)csc(x)= 1/f is x=arccos(f)+2pin,x=-arccos(f)+2pin

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solvefor x,tan(x)csc(x)= 1/f

solve for

x, tan (x) csc (x) = \frac{1}{f}

x = arccos (f) + 2 πn, x = - arccos (f) + 2 πn

Solution steps

tan (x) csc (x) = \frac{1}{f}

Subtract

\frac{1}{f}

from both sides

tan (x) csc (x) - \frac{1}{f} = 0

Simplify

tan (x) csc (x) - \frac{1}{f} : \frac{f tan ( x ) csc ( x ) - 1}{f}

\frac{f tan ( x ) csc ( x ) - 1}{f} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

f tan (x) csc (x) - 1 = 0

Express with sin, cos

\frac{- cos ( x ) + f}{cos ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

- cos (x) + f = 0

Move

f

to the right side

- cos (x) = - f

Divide both sides by

- 1

cos (x) = f

Apply trig inverse properties

x = arccos (f) + 2 πn, x = - arccos (f) + 2 πn

sin (x) = \frac{10.7}{71.5}

cos (y) = 1

sec (x) = - 3

1.5 = \frac{sin ( 4 5 ^{\circ} )}{sin ( x )}

sin (4 x) + sin (6 x) = 0

What is the general solution for solvefor x,tan(x)csc(x)= 1/f ?
The general solution for solvefor x,tan(x)csc(x)= 1/f is x=arccos(f)+2pin,x=-arccos(f)+2pin