What is the general solution for sin(2θ)=(sqrt(3))/2 ,0<= θ<= 2pi ?

The general solution for sin(2θ)=(sqrt(3))/2 ,0<= θ<= 2pi is θ= pi/6 ,θ= pi/3 ,θ=(7pi)/6 ,θ=(4pi)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(2θ)=(sqrt(3))/2 ,0<= θ<= 2pi

sin (2 θ) = \frac{3}{2}, 0 \leq θ \leq 2 π

θ = \frac{π}{6}, θ = \frac{π}{3}, θ = \frac{7 π}{6}, θ = \frac{4 π}{3}

Solution steps

sin (2 θ) = \frac{3}{2}, 0 \leq θ \leq 2 π

General solutions for

sin (2 θ) = \frac{3}{2}

2 θ = \frac{π}{3} + 2 πn, 2 θ = \frac{2 π}{3} + 2 πn

Solve

2 θ = \frac{π}{3} + 2 πn : θ = \frac{π}{6} + πn

Solve

2 θ = \frac{2 π}{3} + 2 πn : θ = \frac{π}{3} + πn

θ = \frac{π}{6} + πn, θ = \frac{π}{3} + πn

Solutions for the range

0 \leq θ \leq 2 π

θ = \frac{π}{6}, θ = \frac{π}{3}, θ = \frac{7 π}{6}, θ = \frac{4 π}{3}

- 6 sin^{2} (x) = cos (2 x) - 2

\frac{sin ( x )}{sin ( 2 x )} = \frac{1}{2}

- 4 cos (2 θ) - 19 = - 26 cos (θ)

x, z = e^{y} - 3 sin (x y)

tan (4 x + 6) = - 0.272

What is the general solution for sin(2θ)=(sqrt(3))/2 ,0<= θ<= 2pi ?
The general solution for sin(2θ)=(sqrt(3))/2 ,0<= θ<= 2pi is θ= pi/6 ,θ= pi/3 ,θ=(7pi)/6 ,θ=(4pi)/3