What is the general solution for 3cos(θ)-1=-1 ?

The general solution for 3cos(θ)-1=-1 is θ= pi/2+2pin,θ=(3pi)/2+2pin

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3cos(θ)-1=-1

3 cos (θ) - 1 = - 1

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Solution steps

3 cos (θ) - 1 = - 1

Add

1

to both sides

3 cos (θ) - 1 + 1 = - 1 + 1

Simplify

3 cos (θ) = 0

Divide both sides by

3

cos (θ) = 0

General solutions for

cos (θ) = 0

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

2 - 4 cos (x) = 0

csc (2 x) - 4 = 0

8 cos (2 x) = 42

sin (6 0^{\circ} - x) = 2 sin (x)

tan (x) = π

What is the general solution for 3cos(θ)-1=-1 ?
The general solution for 3cos(θ)-1=-1 is θ= pi/2+2pin,θ=(3pi)/2+2pin