What is the general solution for 2sin(θ)+4=4 ?

The general solution for 2sin(θ)+4=4 is θ=2pin,θ=pi+2pin

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2sin(θ)+4=4

2 sin (θ) + 4 = 4

θ = 2 πn, θ = π + 2 πn

Solution steps

2 sin (θ) + 4 = 4

Subtract

4

from both sides

2 sin (θ) + 4 - 4 = 4 - 4

Simplify

2 sin (θ) = 0

Divide both sides by

2

sin (θ) = 0

General solutions for

sin (θ) = 0

θ = 0 + 2 πn, θ = π + 2 πn

Solve

θ = 0 + 2 πn : θ = 2 πn

θ = 2 πn, θ = π + 2 πn

4 sin^{2} (x) + (23 + 2) sin (x) + 3 = 0

- cos (x) - 2 cos^{2} (x) = 0

3 csc (x) = 2 csc (x) + 2

sec (x) = tan (x) + cot (x)

cos (3 x) = - \frac{1}{2} 3

What is the general solution for 2sin(θ)+4=4 ?
The general solution for 2sin(θ)+4=4 is θ=2pin,θ=pi+2pin