What is the general solution for sin(x^2)=cos(x^2) ?

The general solution for sin(x^2)=cos(x^2) is x=(sqrt(pi+4pin))/2 ,x=-(sqrt(pi+4pin))/2

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sin(x^2)=cos(x^2)

sin (x^{2}) = cos (x^{2})

x = \frac{π + 4 πn}{2}, x = - \frac{π + 4 πn}{2}

Solution steps

sin (x^{2}) = cos (x^{2})

Rewrite using trig identities

tan (x^{2}) = 1

General solutions for

tan (x^{2}) = 1

x^{2} = \frac{π}{4} + πn

Solve

x^{2} = \frac{π}{4} + πn : x = \frac{π + 4 πn}{2}, x = - \frac{π + 4 πn}{2}

x = \frac{π + 4 πn}{2}, x = - \frac{π + 4 πn}{2}

sin (2 x - 10) = cos (x + 1 0^{\circ})

4 sin^{2} (x) + 8 sin (x) + 4 = 0

- 4 cos (θ) + 3 = 3

sin (2 x - 8) = sin (x - 4)

0 = 3 cos (x) + sin (x)

What is the general solution for sin(x^2)=cos(x^2) ?
The general solution for sin(x^2)=cos(x^2) is x=(sqrt(pi+4pin))/2 ,x=-(sqrt(pi+4pin))/2