What is the general solution for -4sin(2θ)=0 ?

The general solution for -4sin(2θ)=0 is θ=pin,θ= pi/2+pin

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-4sin(2θ)=0

- 4 sin (2 θ) = 0

θ = πn, θ = \frac{π}{2} + πn

Solution steps

- 4 sin (2 θ) = 0

Divide both sides by

- 4

sin (2 θ) = 0

General solutions for

sin (2 θ) = 0

2 θ = 0 + 2 πn, 2 θ = π + 2 πn

Solve

2 θ = 0 + 2 πn : θ = πn

Solve

2 θ = π + 2 πn : θ = \frac{π}{2} + πn

θ = πn, θ = \frac{π}{2} + πn

tan (2 θ) + tan (θ) = 0

2 sin (x) cos (x) = - sin (x)

4 cos (x) = 23

tan (x) = \frac{50}{50}

4 tan (θ) = 4

What is the general solution for -4sin(2θ)=0 ?
The general solution for -4sin(2θ)=0 is θ=pin,θ= pi/2+pin