What is the general solution for 7cos(7x)=0 ?

The general solution for 7cos(7x)=0 is x= pi/(14)+(2pin)/7 ,x=(3pi}{14}+\frac{2pin)/7

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7cos(7x)=0

7 cos (7 x) = 0

x = \frac{π}{14} + \frac{2 πn}{7}, x = \frac{3 π}{14} + \frac{2 πn}{7}

Solution steps

7 cos (7 x) = 0

Divide both sides by

7

cos (7 x) = 0

General solutions for

cos (7 x) = 0

7 x = \frac{π}{2} + 2 πn, 7 x = \frac{3 π}{2} + 2 πn

Solve

7 x = \frac{π}{2} + 2 πn : x = \frac{π}{14} + \frac{2 πn}{7}

Solve

7 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{14} + \frac{2 πn}{7}

x = \frac{π}{14} + \frac{2 πn}{7}, x = \frac{3 π}{14} + \frac{2 πn}{7}

0.75 = sin (x)

7 cos^{2} (x) - 1 = 5 cos (x), 0 \leq x \leq 2 π

2 cos^{2} (θ) = 3 sin (θ) + 3

cos (π x^{2}) = 0

sin^{2} (θ) + sin (θ) = 0, 0 \leq θ < 2 π

What is the general solution for 7cos(7x)=0 ?
The general solution for 7cos(7x)=0 is x= pi/(14)+(2pin)/7 ,x=(3pi}{14}+\frac{2pin)/7