What is the general solution for 16tan^2(θ)-1=0 ?

The general solution for 16tan^2(θ)-1=0 is θ=0.24497…+pin,θ=-0.24497…+pin

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16tan^2(θ)-1=0

16 tan^{2} (θ) - 1 = 0

θ = 0.24497 \dots + πn, θ = - 0.24497 \dots + πn

Solution steps

16 tan^{2} (θ) - 1 = 0

Solve by substitution

tan (θ) = \frac{1}{4}, tan (θ) = - \frac{1}{4}

tan (θ) = \frac{1}{4} : θ = arctan (\frac{1}{4}) + πn

tan (θ) = - \frac{1}{4} : θ = arctan (- \frac{1}{4}) + πn

Combine all the solutions

θ = arctan (\frac{1}{4}) + πn, θ = arctan (- \frac{1}{4}) + πn

Show solutions in decimal form

θ = 0.24497 \dots + πn, θ = - 0.24497 \dots + πn

sin^{2} (x) + \frac{5}{14} = \frac{6}{7}

sin (2 θ) - 2 sin (θ) = 0

3 sin (t) + cos (t) = 1

cos^{2} (x) = cos (x) + 1

6 sin^{2} (x) = 7 - 5 cos (x)

What is the general solution for 16tan^2(θ)-1=0 ?
The general solution for 16tan^2(θ)-1=0 is θ=0.24497…+pin,θ=-0.24497…+pin