What is the general solution for 2cos(x)=-sqrt(2),0<= x<2pi ?

The general solution for 2cos(x)=-sqrt(2),0<= x<2pi is x=(3pi)/4 ,x=(5pi)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2cos(x)=-sqrt(2),0<= x<2pi

2 cos (x) = - 2, 0 \leq x < 2 π

x = \frac{3 π}{4}, x = \frac{5 π}{4}

Solution steps

2 cos (x) = - 2, 0 \leq x < 2 π

Divide both sides by

2

cos (x) = - \frac{2}{2}

General solutions for

cos (x) = - \frac{2}{2}

x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn

Solutions for the range

0 \leq x < 2 π

x = \frac{3 π}{4}, x = \frac{5 π}{4}

3 sec (x) csc (x) = 2 csc (x)

(2 sin (x) - 1) (2 cos (x) - 3) = 0

cos (θ) = - \frac{6}{7}

sec (θ) = - 5

sin^{3} (x) = \frac{1}{2}

What is the general solution for 2cos(x)=-sqrt(2),0<= x<2pi ?
The general solution for 2cos(x)=-sqrt(2),0<= x<2pi is x=(3pi)/4 ,x=(5pi)/4