What is the general solution for sqrt(3)tan(2θ)-1=0 ?

The general solution for sqrt(3)tan(2θ)-1=0 is θ= pi/(12)+(pin)/2

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sqrt(3)tan(2θ)-1=0

3 tan (2 θ) - 1 = 0

θ = \frac{π}{12} + \frac{πn}{2}

Solution steps

3 tan (2 θ) - 1 = 0

Move

1

to the right side

3 tan (2 θ) = 1

Divide both sides by

3

tan (2 θ) = \frac{3}{3}

General solutions for

tan (2 θ) = \frac{3}{3}

2 θ = \frac{π}{6} + πn

Solve

2 θ = \frac{π}{6} + πn : θ = \frac{π}{12} + \frac{πn}{2}

θ = \frac{π}{12} + \frac{πn}{2}

3 cos^{2} (θ) - 1 = 2 cos (θ)

cos (\frac{x}{2}) = sin (x)

4 sin^{2} (x) - 5 sin (x) + 1 = 0

tan (x) = - 0.6293

2 cos (\frac{2 x}{3}) - 3 = 0

What is the general solution for sqrt(3)tan(2θ)-1=0 ?
The general solution for sqrt(3)tan(2θ)-1=0 is θ= pi/(12)+(pin)/2