What is the general solution for 2cos(2x+(3pi)/2)=sqrt(3) ?

The general solution for 2cos(2x+(3pi)/2)=sqrt(3) is x=pin-(2pi)/3 ,x=pin+pi/6

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2cos(2x+(3pi)/2)=sqrt(3)

2 cos (2 x + \frac{3 π}{2}) = 3

x = πn - \frac{2 π}{3}, x = πn + \frac{π}{6}

Solution steps

2 cos (2 x + \frac{3 π}{2}) = 3

Divide both sides by

2

cos (2 x + \frac{3 π}{2}) = \frac{3}{2}

General solutions for

cos (2 x + \frac{3 π}{2}) = \frac{3}{2}

2 x + \frac{3 π}{2} = \frac{π}{6} + 2 πn, 2 x + \frac{3 π}{2} = \frac{11 π}{6} + 2 πn

Solve

2 x + \frac{3 π}{2} = \frac{π}{6} + 2 πn : x = πn - \frac{2 π}{3}

Solve

2 x + \frac{3 π}{2} = \frac{11 π}{6} + 2 πn : x = πn + \frac{π}{6}

x = πn - \frac{2 π}{3}, x = πn + \frac{π}{6}

3 sin (x) + 2 cos (x) = 0

2 = sec^{2} (x)

cosh (y) = 2

\frac{sin ( 1 2 ^{\circ} )}{sin ( x )} = \frac{343}{1484}

2 sin (x) - 3 cos (x) = 3

What is the general solution for 2cos(2x+(3pi)/2)=sqrt(3) ?
The general solution for 2cos(2x+(3pi)/2)=sqrt(3) is x=pin-(2pi)/3 ,x=pin+pi/6