What is the general solution for sin(5θ)-17=-18 ?

The general solution for sin(5θ)-17=-18 is θ=(3pi}{10}+\frac{2pin)/5

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sin(5θ)-17=-18

sin (5 θ) - 17 = - 18

θ = \frac{3 π}{10} + \frac{2 πn}{5}

Solution steps

sin (5 θ) - 17 = - 18

Move

17

to the right side

sin (5 θ) = - 1

General solutions for

sin (5 θ) = - 1

5 θ = \frac{3 π}{2} + 2 πn

Solve

5 θ = \frac{3 π}{2} + 2 πn : θ = \frac{3 π}{10} + \frac{2 πn}{5}

θ = \frac{3 π}{10} + \frac{2 πn}{5}

x, z = tan (2 x - y)

cos^{2} (θ) - sin^{2} (θ) = \frac{1}{2}

tan (\frac{x}{9}) = 1

- 1 + sin (x) + 2 cos^{2} (x) = 0

3 + sin (3 x) = 2

What is the general solution for sin(5θ)-17=-18 ?
The general solution for sin(5θ)-17=-18 is θ=(3pi}{10}+\frac{2pin)/5