What is the general solution for cos(2x)=sqrt(2)-cos(2x) ?

The general solution for cos(2x)=sqrt(2)-cos(2x) is x= pi/8+pin,x=(7pi)/8+pin

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cos(2x)=sqrt(2)-cos(2x)

cos (2 x) = 2 - cos (2 x)

x = \frac{π}{8} + πn, x = \frac{7 π}{8} + πn

Solution steps

cos (2 x) = 2 - cos (2 x)

Solve by substitution

cos (2 x) = \frac{2}{2}

cos (2 x) = \frac{2}{2} : x = \frac{π}{8} + πn, x = \frac{7 π}{8} + πn

Combine all the solutions

x = \frac{π}{8} + πn, x = \frac{7 π}{8} + πn

tan (x) = \frac{6.7}{4.9}

tan (2 a) = 2

5 cos^{2} (x) + 6 cos (x) = 8

tan (x) = \frac{- 4}{3}

sin (x) = \frac{2.5}{5}

What is the general solution for cos(2x)=sqrt(2)-cos(2x) ?
The general solution for cos(2x)=sqrt(2)-cos(2x) is x= pi/8+pin,x=(7pi)/8+pin