What is the general solution for 3sqrt(2)sec(θ)+7=1 ?

The general solution for 3sqrt(2)sec(θ)+7=1 is θ=(3pi)/4+2pin,θ=(5pi)/4+2pin

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3sqrt(2)sec(θ)+7=1

32 sec (θ) + 7 = 1

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

Solution steps

32 sec (θ) + 7 = 1

Move

7

to the right side

32 sec (θ) = - 6

Divide both sides by

32

sec (θ) = - 2

General solutions for

sec (θ) = - 2

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

cos (x) + cos^{2} (x) - sin^{2} (x) = 0

x, 2 sin (x) + csc (x) = 0

4 cos^{2} (x) + 4 = 6

sin (2 x + \frac{π}{6}) = - \frac{1}{2}

sin (θ) = - \frac{11}{6}

What is the general solution for 3sqrt(2)sec(θ)+7=1 ?
The general solution for 3sqrt(2)sec(θ)+7=1 is θ=(3pi)/4+2pin,θ=(5pi)/4+2pin