What is the general solution for 2sin^2(x)-7cos(x)+2=0 ?

The general solution for 2sin^2(x)-7cos(x)+2=0 is x= pi/3+2pin,x=(5pi)/3+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2sin^2(x)-7cos(x)+2=0

2 sin^{2} (x) - 7 cos (x) + 2 = 0

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Solution steps

2 sin^{2} (x) - 7 cos (x) + 2 = 0

Rewrite using trig identities

4 - 2 cos^{2} (x) - 7 cos (x) = 0

Solve by substitution

cos (x) = - 4, cos (x) = \frac{1}{2}

cos (x) = - 4 :

No Solution

cos (x) = \frac{1}{2} : x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Combine all the solutions

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

5 cos (θ) = 0

sin (2 θ) = 4 cos (θ)

tan (θ) = \frac{4}{4}

tan (θ) = \frac{4}{6}

tan (θ) = \frac{4}{7}

What is the general solution for 2sin^2(x)-7cos(x)+2=0 ?
The general solution for 2sin^2(x)-7cos(x)+2=0 is x= pi/3+2pin,x=(5pi)/3+2pin