What is the general solution for sin(4θ)=-(sqrt(3))/2 ?

The general solution for sin(4θ)=-(sqrt(3))/2 is θ= pi/3+(pin)/2 ,θ=(5pi}{12}+\frac{pin)/2

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sin(4θ)=-(sqrt(3))/2

sin (4 θ) = - \frac{3}{2}

θ = \frac{π}{3} + \frac{πn}{2}, θ = \frac{5 π}{12} + \frac{πn}{2}

Solution steps

sin (4 θ) = - \frac{3}{2}

General solutions for

sin (4 θ) = - \frac{3}{2}

4 θ = \frac{4 π}{3} + 2 πn, 4 θ = \frac{5 π}{3} + 2 πn

Solve

4 θ = \frac{4 π}{3} + 2 πn : θ = \frac{π}{3} + \frac{πn}{2}

Solve

4 θ = \frac{5 π}{3} + 2 πn : θ = \frac{5 π}{12} + \frac{πn}{2}

θ = \frac{π}{3} + \frac{πn}{2}, θ = \frac{5 π}{12} + \frac{πn}{2}

1 = 6 cos (x)

x, sec (x) = 0

sin (\frac{x}{3}) = \frac{3}{2}

2 cos (θ) sin (θ) - cos (θ) = 0

- sin (x) = cos (2 x)

What is the general solution for sin(4θ)=-(sqrt(3))/2 ?
The general solution for sin(4θ)=-(sqrt(3))/2 is θ= pi/3+(pin)/2 ,θ=(5pi}{12}+\frac{pin)/2