What is the general solution for -1/2 =cos(θ) ?

The general solution for -1/2 =cos(θ) is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin

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-1/2 =cos(θ)

- \frac{1}{2} = cos (θ)

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

Solution steps

- \frac{1}{2} = cos (θ)

Switch sides

cos (θ) = - \frac{1}{2}

General solutions for

cos (θ) = - \frac{1}{2}

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

4 cos^{2} (x) - 3 cos (x) - 2 = 0

sin (x) = cos (3 x)

x, y = 5 sin (\frac{x}{4})

3 sin (\frac{π}{3} x) = 2

cos^{2} (x) = \frac{1}{3}

What is the general solution for -1/2 =cos(θ) ?
The general solution for -1/2 =cos(θ) is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin