What is the general solution for sqrt(4cos(θ))=1-cos(θ) ?

The general solution for sqrt(4cos(θ))=1-cos(θ) is θ=1.39837…+2pin,θ=2pi-1.39837…+2pin

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sqrt(4cos(θ))=1-cos(θ)

4 cos (θ) = 1 - cos (θ)

θ = 1.39837 \dots + 2 πn, θ = 2 π - 1.39837 \dots + 2 πn

Solution steps

4 cos (θ) = 1 - cos (θ)

Solve by substitution

cos (θ) = 3 - 22

cos (θ) = 3 - 22 : θ = arccos (3 - 22) + 2 πn, θ = 2 π - arccos (3 - 22) + 2 πn

Combine all the solutions

θ = arccos (3 - 22) + 2 πn, θ = 2 π - arccos (3 - 22) + 2 πn

Show solutions in decimal form

θ = 1.39837 \dots + 2 πn, θ = 2 π - 1.39837 \dots + 2 πn

sin (\frac{x}{3}) = 0

cos (x) = 0.95

2 cos (2 θ) + 2 cos (θ) + 2 = 3 cos (θ)

1 + csc (x) = cot^{2} (x)

cos (\frac{1}{4 θ}) = \frac{- 2}{2}

What is the general solution for sqrt(4cos(θ))=1-cos(θ) ?
The general solution for sqrt(4cos(θ))=1-cos(θ) is θ=1.39837…+2pin,θ=2pi-1.39837…+2pin