What is the general solution for 2sin(pi/4-x)+sqrt(3)=0 ?

The general solution for 2sin(pi/4-x)+sqrt(3)=0 is x=-2pin-(13pi)/(12),x=-2pin-(17pi)/(12)

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2sin(pi/4-x)+sqrt(3)=0

2 sin (\frac{π}{4} - x) + 3 = 0

x = - 2 πn - \frac{13 π}{12}, x = - 2 πn - \frac{17 π}{12}

Solution steps

2 sin (\frac{π}{4} - x) + 3 = 0

Move

3

to the right side

2 sin (\frac{π}{4} - x) = - 3

Divide both sides by

2

sin (\frac{π}{4} - x) = - \frac{3}{2}

General solutions for

sin (\frac{π}{4} - x) = - \frac{3}{2}

\frac{π}{4} - x = \frac{4 π}{3} + 2 πn, \frac{π}{4} - x = \frac{5 π}{3} + 2 πn

Solve

\frac{π}{4} - x = \frac{4 π}{3} + 2 πn : x = - 2 πn - \frac{13 π}{12}

Solve

\frac{π}{4} - x = \frac{5 π}{3} + 2 πn : x = - 2 πn - \frac{17 π}{12}

x = - 2 πn - \frac{13 π}{12}, x = - 2 πn - \frac{17 π}{12}

3.1 = 48.1 (1 - cos (\frac{28.66 x}{48.1}))

sin^{2} (x) - 2 cos (x) = - 2

2 cos^{2} (x) + 6 = 7

3 sin (θ) - 2 = 0

1 - csc^{2} (x) = - 3

What is the general solution for 2sin(pi/4-x)+sqrt(3)=0 ?
The general solution for 2sin(pi/4-x)+sqrt(3)=0 is x=-2pin-(13pi)/(12),x=-2pin-(17pi)/(12)