What is the general solution for 5sin(2x)=2cos(2x) ?

The general solution for 5sin(2x)=2cos(2x) is x=(0.38050…)/2+(pin)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5sin(2x)=2cos(2x)

5 sin (2 x) = 2 cos (2 x)

x = \frac{0.38050 \dots}{2} + \frac{πn}{2}

Solution steps

5 sin (2 x) = 2 cos (2 x)

Rewrite using trig identities

5 tan (2 x) = 2

Divide both sides by

5

tan (2 x) = \frac{2}{5}

Apply trig inverse properties

2 x = arctan (\frac{2}{5}) + πn

Solve

2 x = arctan (\frac{2}{5}) + πn : x = \frac{arctan ( \frac{2}{5} )}{2} + \frac{πn}{2}

x = \frac{arctan ( \frac{2}{5} )}{2} + \frac{πn}{2}

Show solutions in decimal form

x = \frac{0.38050 \dots}{2} + \frac{πn}{2}

tan (2 θ - 1 0^{\circ}) = cot (θ)

sinh (x) = 4

2 cos^{2} (θ) - 3 cos (θ) + 1 = 0, 0 \leq θ < 2 π

cos (x) sin (x) = 1

24 arctan (x) = 4 π

What is the general solution for 5sin(2x)=2cos(2x) ?
The general solution for 5sin(2x)=2cos(2x) is x=(0.38050…)/2+(pin)/2