What is the general solution for 0=1+2sin(θ) ?

The general solution for 0=1+2sin(θ) is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin

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0=1+2sin(θ)

0 = 1 + 2 sin (θ)

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

Solution steps

0 = 1 + 2 sin (θ)

Switch sides

1 + 2 sin (θ) = 0

Move

1

to the right side

2 sin (θ) = - 1

Divide both sides by

2

sin (θ) = - \frac{1}{2}

General solutions for

sin (θ) = - \frac{1}{2}

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

csc (x - \frac{π}{3}) = 2

sin (θ) = \frac{11}{6}

x, 5 cos (5 x) = 0

sin (3 x) - sin (5 x) = 0

tan (x) = \frac{5}{13}

What is the general solution for 0=1+2sin(θ) ?
The general solution for 0=1+2sin(θ) is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin