What is the general solution for sin(2x-pi/3)=-1/2 ?

The general solution for sin(2x-pi/3)=-1/2 is x=pin+(3pi)/4 ,x=pin+(13pi)/(12)

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sin(2x-pi/3)=-1/2

sin (2 x - \frac{π}{3}) = - \frac{1}{2}

x = πn + \frac{3 π}{4}, x = πn + \frac{13 π}{12}

Solution steps

sin (2 x - \frac{π}{3}) = - \frac{1}{2}

General solutions for

sin (2 x - \frac{π}{3}) = - \frac{1}{2}

2 x - \frac{π}{3} = \frac{7 π}{6} + 2 πn, 2 x - \frac{π}{3} = \frac{11 π}{6} + 2 πn

Solve

2 x - \frac{π}{3} = \frac{7 π}{6} + 2 πn : x = πn + \frac{3 π}{4}

Solve

2 x - \frac{π}{3} = \frac{11 π}{6} + 2 πn : x = πn + \frac{13 π}{12}

x = πn + \frac{3 π}{4}, x = πn + \frac{13 π}{12}

2 cos (α) = 3 tan (α)

3 tan^{2} (θ) + 7 tan (θ) - 2 = - 4

8 sin (2 x) + 1 = 6

\frac{( 1 - cos ( x ) ) ( csc ^{2} ( x ) - 4 )}{1 + cos ( x )} = 0

6 sin (a) + 4 = 2 sin (a) + 8

What is the general solution for sin(2x-pi/3)=-1/2 ?
The general solution for sin(2x-pi/3)=-1/2 is x=pin+(3pi)/4 ,x=pin+(13pi)/(12)