What is the general solution for sqrt(2)+2cos(x)=0 ?

The general solution for sqrt(2)+2cos(x)=0 is x=(3pi)/4+2pin,x=(5pi)/4+2pin

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sqrt(2)+2cos(x)=0

2 + 2 cos (x) = 0

x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn

Solution steps

2 + 2 cos (x) = 0

Move

2

to the right side

2 cos (x) = - 2

Divide both sides by

2

cos (x) = - \frac{2}{2}

General solutions for

cos (x) = - \frac{2}{2}

x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn

2 sin (θ) sec (θ) = 4 sin (θ)

sec (x - \frac{π}{7}) cos (x - \frac{π}{7}) = sin (x - \frac{π}{7})

cos (x) = \frac{17}{28}

sec^{4} (x) - 4 sec^{2} (x) = 0

\frac{cos ( x )}{sec ( x )} - \frac{sin ( x )}{csc ( x )} = 1

What is the general solution for sqrt(2)+2cos(x)=0 ?
The general solution for sqrt(2)+2cos(x)=0 is x=(3pi)/4+2pin,x=(5pi)/4+2pin