What is the general solution for 1+sqrt(2)sin(x)=cos(2x) ?

The general solution for 1+sqrt(2)sin(x)=cos(2x) is x=2pin,x=pi+2pin,x=(5pi)/4+2pin,x=(7pi)/4+2pin

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1+sqrt(2)sin(x)=cos(2x)

1 + 2 sin (x) = cos (2 x)

x = 2 πn, x = π + 2 πn, x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Solution steps

1 + 2 sin (x) = cos (2 x)

Subtract

cos (2 x)

from both sides

1 + 2 sin (x) - cos (2 x) = 0

Rewrite using trig identities

2 sin^{2} (x) + sin (x) 2 = 0

Solve by substitution

sin (x) = 0, sin (x) = - \frac{2}{2}

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = - \frac{2}{2} : x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn, x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

12 - sin (θ) = cos (2 θ)

2 cos (θ) = 3

(\frac{1}{2}) sin^{2} (x) = 1

3 = 4 sin (θ)

- 6 sin (x) = 0

What is the general solution for 1+sqrt(2)sin(x)=cos(2x) ?
The general solution for 1+sqrt(2)sin(x)=cos(2x) is x=2pin,x=pi+2pin,x=(5pi)/4+2pin,x=(7pi)/4+2pin