What is the general solution for solvefor θ,x=rcos(θ) ?

The general solution for solvefor θ,x=rcos(θ) is θ=arccos(x/r)+2pin,θ=-arccos(x/r)+2pin

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solvefor θ,x=rcos(θ)

solve for

θ, x = r cos (θ)

θ = arccos (\frac{x}{r}) + 2 πn, θ = - arccos (\frac{x}{r}) + 2 πn

Solution steps

x = r cos (θ)

Switch sides

r cos (θ) = x

Divide both sides by

r; r \neq = 0

cos (θ) = \frac{x}{r}; r \neq = 0

Apply trig inverse properties

θ = arccos (\frac{x}{r}) + 2 πn, θ = - arccos (\frac{x}{r}) + 2 πn

1 + sec^{2} (x) = 3

2 cos (a) sin (a) - 4 cos (a) + 6 sin (a) - 12 = 0

cos (x) = \frac{83}{92}

sin (\frac{π}{4} x) = 1

3 cos (x) + 1 = - 2 cos^{2} (x)

What is the general solution for solvefor θ,x=rcos(θ) ?
The general solution for solvefor θ,x=rcos(θ) is θ=arccos(x/r)+2pin,θ=-arccos(x/r)+2pin