What is the general solution for tan(θ)=(2sqrt(3))/2 ?

The general solution for tan(θ)=(2sqrt(3))/2 is θ= pi/3+pin

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tan(θ)=(2sqrt(3))/2

tan (θ) = \frac{2 3}{2}

θ = \frac{π}{3} + πn

Degrees

θ = 6 0^{\circ} + 18 0^{\circ} n

Solution steps

tan (θ) = \frac{2 3}{2}

Divide the numbers:

\frac{2}{2} = 1

tan (θ) = 3

General solutions for

tan (θ) = 3

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

θ = \frac{π}{3} + πn

θ = \frac{π}{3} + πn

sec^{2} (x) + 2 tan (x) = 0

tan (x) = - 12, cos (x) > 0

sin (π x) + cos (π x) = 0

cos (θ) sin (θ) - 4 cos (θ) = 0

sec (x) sin (x) = 2 sin (x)

What is the general solution for tan(θ)=(2sqrt(3))/2 ?
The general solution for tan(θ)=(2sqrt(3))/2 is θ= pi/3+pin