What is the general solution for 2sin(θ/3)+sqrt(3)=0,0<= θ<= 2pi ?

The general solution for 2sin(θ/3)+sqrt(3)=0,0<= θ<= 2pi is No Solution for θ\in\mathbb{R}

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2sin(θ/3)+sqrt(3)=0,0<= θ<= 2pi

2 sin (\frac{θ}{3}) + 3 = 0, 0 \leq θ \leq 2 π

No Solution for θ \in R

Solution steps

2 sin (\frac{θ}{3}) + 3 = 0, 0 \leq θ \leq 2 π

Move

3

to the right side

2 sin (\frac{θ}{3}) = - 3

Divide both sides by

2

sin (\frac{θ}{3}) = - \frac{3}{2}

General solutions for

sin (\frac{θ}{3}) = - \frac{3}{2}

\frac{θ}{3} = \frac{4 π}{3} + 2 πn, \frac{θ}{3} = \frac{5 π}{3} + 2 πn

Solve

\frac{θ}{3} = \frac{4 π}{3} + 2 πn : θ = 4 π + 6 πn

Solve

\frac{θ}{3} = \frac{5 π}{3} + 2 πn : θ = 5 π + 6 πn

θ = 4 π + 6 πn, θ = 5 π + 6 πn

Solutions for the range

0 \leq θ \leq 2 π

No Solution for θ \in R

sin (2 x) - 2 sin (x) = 0, 0 \leq x \leq 2 π

2 sin (x - \frac{π}{3}) + 3 = 0

sin (x) = 0.77

sin (x) = 0.87

sin (x) = 0.14

What is the general solution for 2sin(θ/3)+sqrt(3)=0,0<= θ<= 2pi ?
The general solution for 2sin(θ/3)+sqrt(3)=0,0<= θ<= 2pi is No Solution for θ\in\mathbb{R}