What is the general solution for (2sin(x)-1)(cos(x)+1)=0 ?

The general solution for (2sin(x)-1)(cos(x)+1)=0 is x= pi/6+2pin,x=(5pi)/6+2pin,x=pi+2pin

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(2sin(x)-1)(cos(x)+1)=0

(2 sin (x) - 1) (cos (x) + 1) = 0

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn, x = π + 2 πn

Solution steps

(2 sin (x) - 1) (cos (x) + 1) = 0

Solving each part separately

2 sin (x) - 1 = 0 or cos (x) + 1 = 0

2 sin (x) - 1 = 0 : x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

cos (x) + 1 = 0 : x = π + 2 πn

Combine all the solutions

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn, x = π + 2 πn

7 sin^{2} (x) - 6 = - 3 sin^{2} (x)

tan (b) = 4

1 sin (3 0^{\circ}) = 1.5 sin (x)

3 - 3 sin (t) = 33 cos (t)

sin (θ) = \frac{3}{10}

What is the general solution for (2sin(x)-1)(cos(x)+1)=0 ?
The general solution for (2sin(x)-1)(cos(x)+1)=0 is x= pi/6+2pin,x=(5pi)/6+2pin,x=pi+2pin