What is the general solution for sin(θ)=-4/7 ,pi<θ<(3pi)/2 ,cos(2θ) ?

The general solution for sin(θ)=-4/7 ,pi<θ<(3pi)/2 ,cos(2θ) is θ=pi+0.60824…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(θ)=-4/7 ,pi<θ<(3pi)/2 ,cos(2θ)

sin (θ) = - \frac{4}{7}, π < θ < \frac{3 π}{2}, cos (2 θ)

θ = π + 0.60824 \dots

Degrees

θ = 214.84990 \dots^{\circ}

Solution steps

sin (θ) = - \frac{4}{7}, π < θ < \frac{3 π}{2}, cos (2 θ)

Apply trig inverse properties

sin (θ) = - \frac{4}{7}

General solutions for

sin (θ) = - \frac{4}{7}

sin (x) = - a \Rightarrow x = arcsin (- a) + 2 πn, x = π + arcsin (a) + 2 πn

θ = arcsin (- \frac{4}{7}) + 2 πn, θ = π + arcsin (\frac{4}{7}) + 2 πn

θ = arcsin (- \frac{4}{7}) + 2 πn, θ = π + arcsin (\frac{4}{7}) + 2 πn

Solutions for the range

π < θ < \frac{3 π}{2}

θ = π + arcsin (\frac{4}{7})

Show solutions in decimal form

θ = π + 0.60824 \dots

tan (θ) = - \frac{2}{5}

(tan (x) - 1) (3 tan (x) + 1) = 0

sec (2 x) + 1 = 0

sin (θ) = - \frac{4}{7}

6 cos (6 x) = 5

What is the general solution for sin(θ)=-4/7 ,pi<θ<(3pi)/2 ,cos(2θ) ?
The general solution for sin(θ)=-4/7 ,pi<θ<(3pi)/2 ,cos(2θ) is θ=pi+0.60824…