What is the general solution for cot^2(x)-2cot(x)+1=0 ?

The general solution for cot^2(x)-2cot(x)+1=0 is x= pi/4+pin

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cot^2(x)-2cot(x)+1=0

cot^{2} (x) - 2 cot (x) + 1 = 0

x = \frac{π}{4} + πn

Solution steps

cot^{2} (x) - 2 cot (x) + 1 = 0

Solve by substitution

cot (x) = 1

cot (x) = 1 : x = \frac{π}{4} + πn

Combine all the solutions

x = \frac{π}{4} + πn

3 sin (x) - 2 = 0

4 cos^{2} (x) - 2 sin (x) + 1 = 0

tan (x) = \frac{3 3}{5}

tan (x) + 1 = - \frac{1}{3} - \frac{1}{3} cot (x)

6 cos^{2} (x) + 7 cos (x) + 2 = 0

What is the general solution for cot^2(x)-2cot(x)+1=0 ?
The general solution for cot^2(x)-2cot(x)+1=0 is x= pi/4+pin