What is the general solution for sin(θ)= 4/5 ,0<θ< pi/2 ,sin(2θ) ?

The general solution for sin(θ)= 4/5 ,0<θ< pi/2 ,sin(2θ) is θ=0.92729…

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sin(θ)= 4/5 ,0<θ< pi/2 ,sin(2θ)

sin (θ) = \frac{4}{5}, 0 < θ < \frac{π}{2}, sin (2 θ)

θ = 0.92729 \dots

Solution steps

sin (θ) = \frac{4}{5}, 0 < θ < \frac{π}{2}, sin (2 θ)

Apply trig inverse properties

θ = arcsin (\frac{4}{5}) + 2 πn, θ = π - arcsin (\frac{4}{5}) + 2 πn

Solutions for the range

0 < θ < \frac{π}{2}

θ = arcsin (\frac{4}{5})

Show solutions in decimal form

θ = 0.92729 \dots

sin (x) - 4 = cos (x) - 4

cos (9 x + 15) = sin (7 x - 5)

3 cos (2 θ) - sin (θ) = 1

\frac{1}{2} - sin (x) = 1

sin (t) + 2 = 3

What is the general solution for sin(θ)= 4/5 ,0<θ< pi/2 ,sin(2θ) ?
The general solution for sin(θ)= 4/5 ,0<θ< pi/2 ,sin(2θ) is θ=0.92729…