What is the general solution for 10cos(2x)=0 ?

The general solution for 10cos(2x)=0 is x= pi/4+pin,x=(3pi)/4+pin

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10cos(2x)=0

10 cos (2 x) = 0

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

10 cos (2 x) = 0

Divide both sides by

10

cos (2 x) = 0

General solutions for

cos (2 x) = 0

2 x = \frac{π}{2} + 2 πn, 2 x = \frac{3 π}{2} + 2 πn

Solve

2 x = \frac{π}{2} + 2 πn : x = \frac{π}{4} + πn

Solve

2 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{4} + πn

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

6 cos^{2} (θ) sin (θ) - 3 cos^{2} (θ) = 0

sin^{2} (x) + 2 sin (x) + 1 = 0, 0 \leq x < 2 π

2 + 7 cos (θ) = 4 sin^{2} (θ)

x, sinh (x) = 0

sin (a) = 0.5

What is the general solution for 10cos(2x)=0 ?
The general solution for 10cos(2x)=0 is x= pi/4+pin,x=(3pi)/4+pin