What is the general solution for 1=2sin(2x) ?

The general solution for 1=2sin(2x) is x= pi/(12)+pin,x=(5pi)/(12)+pin

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1=2sin(2x)

1 = 2 sin (2 x)

x = \frac{π}{12} + πn, x = \frac{5 π}{12} + πn

Solution steps

1 = 2 sin (2 x)

Switch sides

2 sin (2 x) = 1

Divide both sides by

2

sin (2 x) = \frac{1}{2}

General solutions for

sin (2 x) = \frac{1}{2}

2 x = \frac{π}{6} + 2 πn, 2 x = \frac{5 π}{6} + 2 πn

Solve

2 x = \frac{π}{6} + 2 πn : x = \frac{π}{12} + πn

Solve

2 x = \frac{5 π}{6} + 2 πn : x = \frac{5 π}{12} + πn

x = \frac{π}{12} + πn, x = \frac{5 π}{12} + πn

3 cos (θ) = 2

cot (t) = - \frac{1}{3}

sin (2 x) = - 2 sin (x)

cos (x) = - \frac{31}{52019}

csc (\frac{x}{4}) = 2

What is the general solution for 1=2sin(2x) ?
The general solution for 1=2sin(2x) is x= pi/(12)+pin,x=(5pi)/(12)+pin