What is the general solution for sin^2(x)-9cos(x)-9=0 ?

The general solution for sin^2(x)-9cos(x)-9=0 is x=pi+2pin

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sin^2(x)-9cos(x)-9=0

sin^{2} (x) - 9 cos (x) - 9 = 0

x = π + 2 πn

Solution steps

sin^{2} (x) - 9 cos (x) - 9 = 0

Rewrite using trig identities

- 8 - cos^{2} (x) - 9 cos (x) = 0

Solve by substitution

cos (x) = - 8, cos (x) = - 1

cos (x) = - 8 :

No Solution

cos (x) = - 1 : x = π + 2 πn

Combine all the solutions

x = π + 2 πn

sin (a) = \frac{8}{17}

cot (t) = 1

4 sin (x) + 3 = 5

tan (θ) = \frac{3}{3}

cos (x) = - \frac{24}{25}

What is the general solution for sin^2(x)-9cos(x)-9=0 ?
The general solution for sin^2(x)-9cos(x)-9=0 is x=pi+2pin