What is the general solution for sec^2(x)-1=0,0<= x<= 2pi ?

The general solution for sec^2(x)-1=0,0<= x<= 2pi is x=0,x=2pi,x=pi

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sec^2(x)-1=0,0<= x<= 2pi

sec^{2} (x) - 1 = 0, 0 \leq x \leq 2 π

x = 0, x = 2 π, x = π

Solution steps

sec^{2} (x) - 1 = 0, 0 \leq x \leq 2 π

Solve by substitution

sec (x) = 1, sec (x) = - 1

sec (x) = 1, 0 \leq x \leq 2 π : x = 0, x = 2 π

sec (x) = - 1, 0 \leq x \leq 2 π : x = π

Combine all the solutions

x = 0, x = 2 π, x = π

3 cos (\frac{x}{2}) + 3 = cos (\frac{x}{2})

(tan (θ) + 1) (tan (θ) - 3) = 0

\frac{2}{3} cos (3 x) = 1

2 cos^{2} (x) - 2 sin^{2} (x) = 0

csc^{2} (θ) + 5 = 7 - csc (θ)

What is the general solution for sec^2(x)-1=0,0<= x<= 2pi ?
The general solution for sec^2(x)-1=0,0<= x<= 2pi is x=0,x=2pi,x=pi