What is the general solution for 2cos(2x)+3=2 ?

The general solution for 2cos(2x)+3=2 is x= pi/3+pin,x=(2pi)/3+pin

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2cos(2x)+3=2

2 cos (2 x) + 3 = 2

x = \frac{π}{3} + πn, x = \frac{2 π}{3} + πn

Solution steps

2 cos (2 x) + 3 = 2

Move

3

to the right side

2 cos (2 x) = - 1

Divide both sides by

2

cos (2 x) = - \frac{1}{2}

General solutions for

cos (2 x) = - \frac{1}{2}

2 x = \frac{2 π}{3} + 2 πn, 2 x = \frac{4 π}{3} + 2 πn

Solve

2 x = \frac{2 π}{3} + 2 πn : x = \frac{π}{3} + πn

Solve

2 x = \frac{4 π}{3} + 2 πn : x = \frac{2 π}{3} + πn

x = \frac{π}{3} + πn, x = \frac{2 π}{3} + πn

2 cos (x) = sec (x)

tan (5 x) = - 1

x, 7 y^{2} + sin (3 x) = 12 - y^{4}

sin (\frac{π x}{2}) + 1 = 0

sin (x + 6 0^{\circ}) = - 0.4

What is the general solution for 2cos(2x)+3=2 ?
The general solution for 2cos(2x)+3=2 is x= pi/3+pin,x=(2pi)/3+pin