What is the general solution for 4csc(θ)+4=0 ?

The general solution for 4csc(θ)+4=0 is θ=(3pi)/2+2pin

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4csc(θ)+4=0

4 csc (θ) + 4 = 0

θ = \frac{3 π}{2} + 2 πn

Solution steps

4 csc (θ) + 4 = 0

Move

4

to the right side

4 csc (θ) = - 4

Divide both sides by

4

csc (θ) = - 1

General solutions for

csc (θ) = - 1

θ = \frac{3 π}{2} + 2 πn

4 cos^{2} (4 x) - 3 = 0

tan^{2} (x) = cot (x)

2 sin (x) cos (x) sin (x) - cos (x) = 0

tan^{2} (θ) = 0

tan (a) = \frac{7}{8}

What is the general solution for 4csc(θ)+4=0 ?
The general solution for 4csc(θ)+4=0 is θ=(3pi)/2+2pin